(1+1⼀2+1⼀4+1⼀6)×(1⼀2+1⼀4+1⼀6+1⼀8)-(1+1⼀2+1⼀4+1⼀6+1⼀8)怎么计算啊急急急!!!!!

2025-12-17 08:17:53
推荐回答(1个)
回答1:

设A=1/2+1/4+1/6
(1+1/2+1/4+1/6)×(1/2+1/4+1/6+1/8)-(1+1/2+1/4+1/6+1/8)(1/2+1/4+1/6)
=(1+A)*(A+1/8)-(1-A-1/8)*A
=A²+A+(1/8)A+1/8-A²-A-(1/8)A
=1/8